Skip to main content

Convert any number to English word

#include<stdio.h>
#include<string.h>

void toWord(int,int);
char * getPositionValue(int);
char * digitToWord(int);

char  word[100][30];
int i =0;

int main(){

    int j,k,subnumer;
    unsigned long int number;

    printf("Enter any postive number: ");
    scanf("%lu",&number);
 
    if(number ==0){
         printf("Zero");
         return 0;
    }

    while(number){

         if(i==1){
             toWord(number %10,i);
             number = number/10;
         }else{
             toWord(number %100,i);
             number = number/100;
         }

         i++;
       
    }

    printf("Number in word: ");
    *word[i-1] = *word[i-1] - 32;
    for(j=i-1;j>=0;j--){
         printf("%s",word[j]);
    }

    return 0;

}

void toWord(int number,int position){

    char  numberToword[100]={" "};

    if(number ==0){
    }else if (number < 20 ||number %10==0){
         strcpy(numberToword,digitToWord(number));
    }else{
         strcpy(numberToword,digitToWord((number/10)*10));
         strcat(numberToword,digitToWord(number%10));
    }
 
    strcat(numberToword,getPositionValue(position));
    strcpy(word[i],numberToword);
}

char * getPositionValue(int postion){

    static char positionValue[10]=" ";
 
    switch(postion){

         case 1: strcpy(positionValue,"hundreds "); break;
         case 2: strcpy(positionValue,"thousand "); break;
         case 3: strcpy(positionValue,"lakh "); break;
         case 4: strcpy(positionValue,"crore "); break;
         case 5: strcpy(positionValue,"arab "); break;
         case 6: strcpy(positionValue,"kharab "); break;
         case 7: strcpy(positionValue,"neel "); break;
         case 8: strcpy(positionValue,"padam "); break;
    }
   
    return positionValue;
}

char * digitToWord(int digit){

     static char digitInWord[10]=" ";

    switch(digit){
         case 1: strcpy(digitInWord , "one "); break;
         case 2: strcpy(digitInWord , "two "); break;
         case 3: strcpy(digitInWord , "three "); break;
         case 4: strcpy(digitInWord , "four "); break;
         case 5: strcpy(digitInWord , "five "); break;
         case 6: strcpy(digitInWord , "six "); break;
         case 7: strcpy(digitInWord , "seven "); break;
         case 8: strcpy(digitInWord , "eight "); break;
         case 9: strcpy(digitInWord , "nine ");break;
         case 10: strcpy(digitInWord , "ten "); break;
         case 11: strcpy(digitInWord , "eleven "); break;
         case 12: strcpy(digitInWord , "twelve "); break;
         case 13: strcpy(digitInWord , "thirteen "); break;
         case 14: strcpy(digitInWord , "fourteen "); break;
         case 15: strcpy(digitInWord , "fifteen "); break;
         case 16: strcpy(digitInWord , "sixteen "); break;
         case 17: strcpy(digitInWord , "seventeen "); break;
         case 18: strcpy(digitInWord , "eighteen "); break;
         case 19: strcpy(digitInWord , "nineteen "); break;
         case 20: strcpy(digitInWord , "twenty "); break;
         case 30: strcpy(digitInWord , "thirty "); break;
         case 40: strcpy(digitInWord , "fourty "); break;
         case 50: strcpy(digitInWord , "fifty "); break;
         case 60: strcpy(digitInWord , "sixty "); break;
         case 70: strcpy(digitInWord , "seventy "); break;
         case 80: strcpy(digitInWord , "eighty "); break;
         case 90: strcpy(digitInWord,"ninety "); break;
    }
 
    return digitInWord;
}

Popular posts from this blog

C++ Program to find the sum, difference, product and quotient of two integers

#include <iostream.h> #include <conio.h> void main() {   clrscr();   int x = 10;   int y = 2;   int sum, difference, product, quotient;   sum = x + y;   difference = x - y;   product = x * y;   quotient = x / y;   cout << "The sum of " << x << " & " << y << " is " << sum << "." << endl;   cout << "The difference of " << x << " & " << "y <<  is " << difference << "." << endl;   cout << "The product of " << x << " & " << y << " is " << product << "." << endl;   cout << "The quotient of " << x << " & " << y << " is " << quotient << "." << endl;   getch(); }

Putimage function in c

putimage function outputs a bit image onto the screen. Declaration:- void putimage(int left, int top, void *ptr, int op); putimage puts the bit image previously saved with getimage back onto the screen, with the upper left corner of the image placed at (left, top). ptr points to the area in memory where the source image is stored. The op argument specifies a operator that controls how the color for each destination pixel on screen is computed, based on pixel already on screen and the corresponding source pixel in memory. c smiling face animation This animation using c draws a smiling face which appears at random position on screen. See output below the code, it will help you in understanding the code easily. C programming code #include<graphics.h> #include<conio.h> #include<stdlib.h>   main() { int gd = DETECT, gm, area, temp1, temp2, left = 25, top = 75; void *p;   initgraph(&gd,&gm,"C:\\TC\\BGI");   setcolor(YELLOW)...

What is Dynamic Memory Allocation in C++ Program

In the computer world, anything that is processed be it an instruction or any data first needs to be loaded and located in internal memory.  In C++ programs also any data that is processed while executing the program is held in the internal memory.  What is Dynamic Memory Allocation? Dynamic Memory allocation means that the memory that will be used during the program is not known beforehand and is allocated dynamically and on the go. It is allocated during the runtime as and when required by the program. In C++ there are two operators used in dynamic memory allocation  1. New  2. Delete New operator in dynamic memory allocation The new operator in C++ is used to create objects of all types. The new operator will allocate memory of the size of the data type specified in the program.  For Example iptr = new int ;  Storing initial values will allocate needed amount of memory from the free store to hold the value of the specified data-type and store the startin...